Question

Bill Gates wrote a computer program that generates three random numbers

Answer 1

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

$p(AB)=p(A)\cdot p(B)$ (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

$s=1$

So, the probability of drawing a 3 in 1 draw is

$p(3)=\frac{s}{n}=\frac{1}{10}$

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

$p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}$