45
Mark brainliest please
Hope this helps
This is a right angle triangle problem
drawing a vertical line at from the point where the ramp touches the car park leaves a right angle triangle with the
opposite being 2m
hypothenus being 10m
adjacent unknown
we could use sine
SineO equal to opposite over hypothenus
SineO equal to 2/10
SineO equal to 0.2
O equal to Sine^1(0.2)
O equal to 11 .5
The angle between the ramp and the horizontal is 11.5 degrees
Answer:
DE≈16.1
m<E≈60.3
m<D≈29.7
Step-by-step explanation:
Answer:
30(2+3)
Step-by-step explanation:
1) Find GCF of 60 and 90 (30)
2) Divide both by GCF
3) Put GCF in front of parentheses, then add quotients within the parentheses
1. x = 118 2. x = -54 3. x = -54 4. x = -54
