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jeyben [28]
3 years ago
11

Each season a school basketball team plays 3 practice games and then plays 2 regular seasons games against each of x teams. Whic

h expression represents the total number of practice and regular seasons games played by the school basketball team in a season?
Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

3x+2x=total number

Step-by-step explanation:

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Shelly paid $8.84 for a pizza. This amount includes a sales tax of 4%. What was the cost of the pizza before tax?
lorasvet [3.4K]

Answer:

$8.50

Step-by-step explanation:

let the price before tax be $x

given that the sales tax rate is 4%, hence the amount she paid in taxes

= 4% of x

= (4/100)x

= 0.04x

We can now build an equation for what she paid:

Amount Paid = price before tax + amount paid in taxes

8.84 = x + 0.04x

8.84 = 1.04x   (divide both sides by 1.04 and rearranging)

x = 8.84 / 1.04

x = $8.50

7 0
3 years ago
Read 2 more answers
A 10​-ft vertical post casts a 12​-in shadow at the same time a nearby cell phone tower casts a 126​-ft shadow. How tall is the
SVEN [57.7K]

The cell phone tower is 1260 feet tall

<em><u>Solution:</u></em>

Given that 10​-ft vertical post casts a 12​-in shadow

At the same time a nearby cell phone tower casts a 126​-ft shadow

To find: height of cellphone tower

We can use proportion to solve the sum

\frac{\text {height of post }}{\text {shadow of post}}=\frac{\text {height of tower}}{\text {shadow of tower}}

Here,

Let "x" be the height of tower

height of post = 10 feet

shadow of tower = 126 feet

shadow of post = 12 inches

We know that,

1 inches = 0.0833333 foot

12 inches = 12 x 0.0833333 foot = 1 foot

shadow of post = 1 foot

Thus the proportion becomes,

\frac{10}{1} = \frac{x}{126}

10 \times 126 = x \times 1\\\\x = 10 \times 126 = 1260

Thus the cell phone tower is 1260 feet tall

5 0
3 years ago
Write a line function with a slope of 5 that passes through the point of (2,1)
Anettt [7]
I believe it’s y=5x-9
5 0
3 years ago
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Hellppppppppppppp please
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i looks like it would be v

8 0
3 years ago
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Log2(x-3)+log2x-log2(x+2)=2
sertanlavr [38]

<u>We are given the equation:</u>

log₂(x-3) + log₂x - log₂(x+2) = 2

<u>When is it defined:</u>

in this equation, log₂(x-3) and log₂(x+2) can only be defined when

x-3 >0 and x+2 > 0

solving for the values of x, we get:

x > 3    and   x > -2

which basically means x > 3

<em>Because we are looking for an inequality which is true for both x>-2 and x>3</em>

Hence, x will have a value greater than 3

<u>Solving for x:</u>

using the product rule <em>[logₐb + logₐc = logₐ(bc)]</em>

log₂[(x-3)(x)] - log₂(x+2) = 2  

using the quotient rule <em>[logₐb - logₐc = logₐ(b/c)]</em>

log₂[(x-3)(x) / (x+2)] = 2

from the property <em>[ aˣ = b  ⇒  logₐb = x]</em>

(x² - 3x) / (x+2) = 2²

x² - 3x = 4x + 8

x² - 7x - 8 = 0

x² + x - 8x - 8 = 0

x(x+1) - 8(x+1) = 0

(x-8)(x+1) = 0

(x-8) = 0    OR    (x+1) = 0

x = 8      OR      x = -1

We know that the equation is defined only for x > 3

We can see that x = 8 satisfies that inequality

Therefore, x = 8

5 0
3 years ago
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