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timurjin [86]
3 years ago
9

The solution to a system of two linear equations is (4, -3). One equation has a slope of 4. The slope of the other line is the n

egative reciprocal of the slope of the first.
The system described above is represented by the following equations:

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

Hello,

First equation is false

Second equation is true

Step-by-step explanation:

1)

(4,-3) is a point of the line y=4x-19  since

-3=?4*4-19

-3=-3

2)

(4,-3) is not a point of the line y=1/4x-2 since

-3=? 1/4*4-2

-3=? 1-2

-3≠-1

I have written that because it is difficult for me to understand

"the negative reciprocal of the slope of the first"

the negative reciprocal of 4 should be -1/4.

Equation y=1/4x-2 is false.

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-x^2=-36 I need help
Gennadij [26K]
You need to first make everything positive:
x^2=36
Then you need to get the square root of each side:
x=6 or -6

Hope this helps :)
4 0
3 years ago
How do you determine whether a sum will be positive, negative, or 0 when adding a positive and a negative integer?
professor190 [17]
If the integers have the same absolute value ... they're the same number
but with different signs ... then their sum is zero.

Example:    (plus) 927 added to (negative) 927  =  zero


If the integers have different absolute values ... they're different numbers with different
signs ... then their sum has the same sign as the one with the bigger absolute value.

Examples:

==>   (plus) 92 added to (negative) 91
         92 and 91 are 1 number apart on the number line.
         The positive number is bigger than the negative number.
         So the sum is  +1 . 

==>    (plus) 35 added to (negative) 37
          35 and 37 are 2 numbers apart on the number line.
          The negative number is bigger than the positive one.
          So the sum is  -2 .
3 0
3 years ago
Prove that if x is an positive real number such that x + x^-1 is an integer, then x^3 + x^-3 is an integer as well.
Shkiper50 [21]

Answer:

By closure property of multiplication and addition of integers,

If x + \dfrac{1}{x} is an integer

∴ \left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right ) is an integer

From which we have;

x^3 + \dfrac{1}{x^3} is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

x + \dfrac{1}{x}

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}

By simplification of the cube of the given integer expressions, we have;

\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )

Therefore, we have;

\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}

By rearranging, we get;

x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )

Given that  x + \dfrac{1}{x} is an integer, from the closure property, the product of two integers is always an integer, we have;

\left ( x + \dfrac{1}{x} \right) ^3 is an integer and 3\cdot \left (x + \dfrac{1}{x} \right ) is also an integer

Similarly the sum of two integers is always an integer, we have;

\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right  ) is an integer

\therefore x^3 + \dfrac{1}{x^3} =   \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= \left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right  ) is an integer

From which we have;

x^3 + \dfrac{1}{x^3} is an integer.

4 0
3 years ago
A bike rental shop rents out bicycles with a flat rate of $6 and then charges $2 per hour a person rents out the bike. Identify
DIA [1.3K]

Answer:

Independent Variable: Number of hours

Dependent Variable: Cost

Equation: C = 2x + 6

Step-by-step explanation:

    The independent variable (x) is the variable that is manipulated. In this instance, that would be the number of hours a person rents out the bike.

    The dependent variable (C) is the variable that is manipulated depending on the value of the independent variable. In this instance, that would be the total cost for renting the bike.

    The total equation would be C = 2x + 6. The coefficient, 2, represents the charge of $2 per hour and the 6 represents the starting charge of $6.

6 0
3 years ago
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