Answer:
bruv this is second grade stuff
Step-by-step explanation:
9
the prime factorization is 99
Answer:
48
Step-by-step explanation:
n/-3=-16
n=-16*-3
n=48
Answer:
One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:
Iaₙ₊₁I < IaₙI
This means that the absolute value of the terms must decrease as n increases.
Then we must have:
![\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-2%29%5En%7D%7Bn%2A3%5En%7D%20%3E%20%5Cfrac%7B%28x%20-2%20%29%5E%7Bn%2B1%7D%7D%7B%28n%20%2B%201%29%2A3%5E%7Bn%2B1%7D%7D)
We can write this as:
![\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-2%29%5En%7D%7Bn%2A3%5En%7D%20%3E%20%5Cfrac%7B%28x%20-2%20%29%5E%7Bn%2B1%7D%7D%7B%28n%20%2B%201%29%2A3%5E%7Bn%2B1%7D%7D%20%3D%20%5Cfrac%7B%28x%20-2%29%5En%7D%7B%28n%20%2B%201%29%2A3%5En%7D%20%2A%20%5Cfrac%7B%28x%20-%202%29%7D%7B3%7D)
If we assume that n is a really big number, then:
n + 1 ≈ 1
And we can write:
![\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-2%29%5En%7D%7Bn%2A3%5En%7D%20%3E%20%5Cfrac%7B%28x%20-2%29%5En%7D%7B%28n%29%2A3%5En%7D%20%2A%20%5Cfrac%7B%28x%20-%202%29%7D%7B3%7D)
Then we have the inequality
![1 > (x - 2)/3](https://tex.z-dn.net/?f=1%20%3E%20%28x%20-%202%29%2F3)
And remember that this must be in absolute value, then we will have that:
-1 < (x - 2)/3 < 1
-3 < x - 2 < 3
-3 + 2 < x < 3 + 2
-1 < x < 5
The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.
Answer: There are 6 bricks in the bag.
Step-by-step explanation:
Convert from mixed number to decimal number. To do it, divide the numerator of the fraction by the denominator and add the result to the whole number part. Then:
![3\frac{3}{4}\ lb=(3+0.75)\ lb=3.75\ lb](https://tex.z-dn.net/?f=3%5Cfrac%7B3%7D%7B4%7D%5C%20lb%3D%283%2B0.75%29%5C%20lb%3D3.75%5C%20lb)
Convert from fraction to decimal number. To do it you need to divide the numerator by the denominator. Then, you get:
![\frac{5}{8}lb=0.625\ lb](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7Dlb%3D0.625%5C%20lb)
Let be "x" the number of bricks in the bag<em>.</em>
<em> </em>Based on the information given in the exercise, you can set up the following proportion:
![\frac{1}{0.625}=\frac{x}{3.75}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.625%7D%3D%5Cfrac%7Bx%7D%7B3.75%7D)
Finally, you must solve for "x" in order to find its value. This is:
![(3.75)(\frac{1}{0.625})=x\\\\x=6](https://tex.z-dn.net/?f=%283.75%29%28%5Cfrac%7B1%7D%7B0.625%7D%29%3Dx%5C%5C%5C%5Cx%3D6)