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Aleksandr-060686 [28]
3 years ago
13

Alan graphed the relationship between temperature and elevation for several cities. The xxx-coordinate is the elevation in meter

s and the yyy-coordinate is the temperature in ^{\circ}\text{C}
∘
Cdegrees, start text, C, end text.

Which quadrant would contain a point showing a city 6 \text{ m}6 m6, start text, space, m, end text above sea level and 9 ^{\circ}\text{C}9
∘
C9, degrees, start text, C, end text below zero?
Mathematics
2 answers:
Shkiper50 [21]3 years ago
7 0

Answer:

Quadrant IV

Step-by-step explanation:

just trust me

NeX [460]3 years ago
5 0

Answer:

Quadrant IV

Step-by-step explanation:

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When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o
borishaifa [10]

Answer:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The expected values for all the categories is :

E_i =\frac{150}{3}=50

And then the statistic would be given by:

\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4

And the best option would be:

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Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The expected values for all the categories is :

E_i =\frac{150}{3}=50

And then the statistic would be given by:

\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4

And the best option would be:

b. 4

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