let's recall that d = rt, distance = rate * time.
he went upstream to a distance "d", got tired and came back to his starting point, so he rowed back a distance "d" exactly.
we know the rates, we also know the trip took 2 hours, let's say on the way over he took "t" hours to get there, on the way back he lasted then "2 - t" hours.
![\stackrel{\textit{substituting on the 2nd equation}}{2t=8(2-t)\implies 2t=16-8t}\implies 10t=16\implies t=\cfrac{16}{10}\implies t=\cfrac{8}{5} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{we know that}}{d=2t}\implies d=2\left( \cfrac{8}{5} \right)\implies \stackrel{\textit{3 miles and 1056 feet}}{d=\cfrac{16}{5}\implies d=3\frac{1}{5}}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B2t%3D8%282-t%29%5Cimplies%202t%3D16-8t%7D%5Cimplies%2010t%3D16%5Cimplies%20t%3D%5Ccfrac%7B16%7D%7B10%7D%5Cimplies%20t%3D%5Ccfrac%7B8%7D%7B5%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20know%20that%7D%7D%7Bd%3D2t%7D%5Cimplies%20d%3D2%5Cleft%28%20%5Ccfrac%7B8%7D%7B5%7D%20%5Cright%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7B3%20miles%20and%201056%20feet%7D%7D%7Bd%3D%5Ccfrac%7B16%7D%7B5%7D%5Cimplies%20d%3D3%5Cfrac%7B1%7D%7B5%7D%7D)
Like terms are any terms that have the same variable value.
In the sequence 8a, b^2, b^3, 4b^2, 4, and 5a, the like terms are the ones that have the same variable to the same power.
8a and 5a are like terms, as well as b^2 and 4b^2, because both sets of terms have the same variable.
Hope that helped =)
You would do 26/60 and turn it into a percentage (43.33333333%)
Answer:
what kind of math412412321424214
Step-by-step explanation:
???12312442141252112
First we write down this expression:
We notice that 36 is a square of 6 so we write:
Now, square root we imply on each of factors (g^6 and 6 ^2)
we get.
6*|g^3|
The reason for absolute value is because of variable g.
Answer is C.
