Answer:
E(X) = 17.4
Step-by-step explanation:
We can calculate the expected value of a random X variable that is discrete (X takes specific values ) as:
E(X) = ∑xp(x) where x are the specific values of x and p(x) the probability associated with this x value.
In this way the expexted value is
E(X) = ∑xp(x) =(16*0.6)+(18*0.3)+(20*0.2) = 8+5.4+4 = 17.4
Answer:
b 12 hats for $48
Step-by-step explanation:
51, 53, 55, 57, 59. it's simple.
Answer:
Step-by-step explanation:
Case I: use common logs:
2x log 3 = log 4, or 2x(0.47712) = 0.60206
Solving for x, we get 0.95424x = 0.60206, and then x = 0.60206/0.95424.
x is then x = 0.631
Case II: use logs to the base 3:
2x (log to the base 3 of 3) = (log to the base 3 of 4)
This simplifies to 2x(1) = 2x = (log 4)/log 3 = 1.262. Finally, we divide this
result by 2, obtaining x = 0.631
