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weeeeeb [17]
2 years ago
5

Which algebraic expression represents this word description?

Mathematics
1 answer:
Damm [24]2 years ago
5 0

Step-by-step explanation:

c. 2x-11 this is the answer

hope this helps you

have a nice day:)

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1 Which expression is equivalent to (7x – 5) – (3x - 2)?​
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Answer:

The answer is D.

Step-by-step explanation:

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3 years ago
Use a given information to create equation for the rational function. The function is written in factored form to help see how t
Mars2501 [29]

Recall that a rational function:

\frac{P(x)}{Q(x)},

has a vertical asymptote at x₀ if and only if:

Q(x_0)=0.

Also, the roots of the above rational function are the same as P(x).

Since the rational function has a vertical asymptote at x=-1, we get that its denominator must be:

Q(x)=x+1\text{.}

Since the rational function has a double zero at x=2 we get that its numerator must be of the form:

P(x)=k(x-2)(x-2)\text{.}

Finally, since the rational function has y-intercept at (0,2) we get that:

2=\frac{P(0)}{Q(0)}=\frac{k(0-2)(0-2)}{0+1}\text{.}

Simplifying the above equation we get:

\begin{gathered} \frac{k(-2)(-2)}{1}=2, \\ 4k=2. \end{gathered}

Dividing the above equation by 4 we get:

\begin{gathered} \frac{4k}{4}=\frac{2}{4}, \\ k=\frac{1}{2}\text{.} \end{gathered}

Therefore, the rational function that satisfies the given conditions is:

f(x)=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}\text{.}

Answer:

The numerator is:

\frac{1}{2}(x-2)(x-2)

The denominator is:

(x+1)

4 0
1 year ago
Please solve the problem with steps
Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}

The first one: (\frac{1}{2})^{n-1} is a geometric sequence of first term (a_1) "1" and common ratio (r) " \frac{1}{2} ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2

The second one: \frac{1}{6^{n-1}} is a geometric sequence of first term "1", and common ratio (r) " \frac{1}{6} ". Again, since the common ratio is smaller than one, we can find its infinite sum:

Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}

8 0
3 years ago
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How did the gulf of Tonkin resolutions affect US involvement in the Vietnam war?
klio [65]

Answer:

I don't know how this is math but...

The Gulf of Tonkin Resolution authorized President Lyndon Johnson to “take all necessary measures to repel any armed attack against the forces of the United States and to prevent further aggression” by the communist government of North Vietnam. Hope I helped! ☺

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2 years ago
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