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VMariaS [17]
3 years ago
15

What is the answer to 8x + 8y + 12

Mathematics
1 answer:
umka21 [38]3 years ago
3 0
Simplifying
8x + 8y = 12

Solving
8x + 8y = 12

Solving for the variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8y' to each side of the equation. 8x + 8y + -8y = 12 + -8y

Combine like terms: 8y + -8y = 0
8x + 0 = 12 + -8y
8x = 12 + -8y

Divide each side by '8'.
x = 1.5 + -1y

Simplifying x = 1.5 + -1y
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Answer:

(2x-3)(-3+2x),(16-x^2)(x²-16),4y^2+25)(25+4y^2)

Step-by-step explanation:

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4 years ago
Step by step how to solve 4x+2=5(x+10)​
Shalnov [3]

Answer:

x = -48

Step-by-step explanation:

4x + 2 = 5(x + 10)

expand the 5(x+10)

4x + 2 = 5x + 50

-2 both sides

4x + 2 - 2 = 5x + 50 - 2

simplify

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4x - 5x = 5x + 48 - 5x

simplify

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÷ (-1) both sides

-x ÷ (-1) = 48 ÷ (-1)

simplify

x = -48

The answer is x = -48.

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3 years ago
What is the slope<br> of the line? I need this for my unit test urgently please help!!!!
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Help me please guys.
Alex_Xolod [135]
15.04 degrees or answer A is correct.


The Law of Sines is the relationship between the sides and angles of non-right (oblique) triangles . Simply, it states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides and angles in a given triangle. The formula for it is A=b•sin a/sin b.


You can transform the law of sines formulas to solve some problems of triangulation (solving a triangle). You can use them to find:

The remaining sides of a triangle, knowing two angles and one side.
The third side of a triangle, knowing two sides and one of the non-enclosed angles. In some cases (ambiguous cases) there may be two solutions to the same triangle. If the following conditions are fulfilled, your triangle may be an ambiguous case:
You only know the angle α and sides a and c;
Angle α is acute (α < 90°);
a is shorter than c (a < c);
a is longer than the altitude h from angle β, where h = c * sin(α) (a > c * sin(α)).

I hate useless complicated math lol ;)
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3 years ago
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