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jeka57 [31]
3 years ago
10

Can someone pls help solve this

Mathematics
1 answer:
Len [333]3 years ago
6 0

Answer:

YOU JUST NEED T APPLY THE FORMULA OF CIRCLE AND IRREGULAR SQUARE AS TRAPEZOIID

Step-by-step explanation:

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Make q the subject of the formula 2(q+p) = 1+5q. Give your answer in the form ap-b/c where a,b and c are all positive integers
musickatia [10]

Answer:

\frac{2p-1}{3}

Step-by-step explanation:

Since you want to get q only and q appears in both side of the equation. Try to isolate q to one side.

1) Expand 2(q+p)

2q + 2p = 1 + 5q

2) Move all q terms to one side

5q - 2q = 2p - 1

3q = 2p - 1

3) Divide 3 on both side (to isolate q)

q = \frac{2p-1}{3}

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4 years ago
Please help time is running out!​
Nataly_w [17]

Answer:

7,1 and 7,2

Hope it helped!!!

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3 years ago
For a family picnic, Edu wants to buy the same number of bratwurst and buns. The bratwurst come in packages of eight and the bun
otez555 [7]

24 because it is the most common multiple of the two.

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Kathryn is getting ready for Halloween and is headed to the store to pick up a costume. At the Halloween store,
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Answer: 30:65

Step-by-step explanation:

7 0
3 years ago
Which of the following represents the vertical asymptotes of the function
Thepotemich [5.8K]
The expression in the denominator is \displaystyle{ x^2-2x-8.

We can use this expression by completing the square, and the difference of squares as follows:

\displaystyle{ x^2-2x-8=(x^2-2x+1)-9=(x-1)^2-3^2

=(x-1-3)(x-1+3)=(x-4)(x+2).

So, the zeros of the polynomial \displaystyle{ P(x)=x^2-2x-8 are x=4 and x=-2.


Thus, the asymptotes are the lines x=-2, and x=4.


Answer: D
8 0
3 years ago
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