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vovikov84 [41]
3 years ago
14

I REALLY NEED HELP

Mathematics
1 answer:
garri49 [273]3 years ago
4 0
Look at the picture.

1.
y=mx+b\\\\m=\dfrac{9}{3}=3\\\\b=4\\\\\boxed{f(x)=3x+4}

2.
f(x)=-2x+3\\\\for\ x=-2\to f(-2)=-2\cdot(-2)+3=4+3=7\to(-2;\ 7)\\for\ x=-1\to f(-1)=-2\cdot(-1)+3=2+3=5\to(-1;\ 5)\\for\ x=0\to f(0)=-2\cdot0+3=3\to(0;\ 3)\\for\ x=1\to f(1)=-2\cdot1+3=-2+3=1\to(1;\ 1)

3.
y=mx+b\\\\m=\dfrac{3}{6}=\dfrac{1}{2}=0.5\\\\b=-3\\\\\boxed{f(x)=0.5x-3}
for\ x=-6\to f(-6)=-6\\for\ x=-2\to f(-2)=-4\\for\ x=0\to f(0)=-3\\for\ x=6\to f(6)=0

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Please help!!!! will mark brainlest
fomenos

Answer: B. 84 in²

Step-by-step explanation:

Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).

Find the area of the rectangle:

Area of a rectangle=length*width

Area of rectangle=(5 in)( 10 in)

Area of rectangle=50 in²

Next, calculate the area of the trapezoid:

Area of trapezoid=\frac{h(b_{1} +b_{2}) }{2}

h=10 in-6 in

h=4 in

b_{1} =15 in

b_{2} =15 in-5 in

b_{2} =10 in

Area of trapezoid=\frac{4in(7 in+10in)}{2}

Area of trapezoid=\frac{4(17in^{2})  }{2}

Area of trapezoid=\frac{68in^{2} }{2}

Area of trapezoid=34in^{2}

Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²

3 0
2 years ago
Which is the value of 10 x 5(2/5)x 4(1/3)?
Molodets [167]

Answer:

26 2/3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
​a valid study select one:
rjkz [21]
I would say A I hope this helps

5 0
3 years ago
Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0
artcher [175]

Answer:

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

f(x,y) = f(0,0) + \frac{df(0,0)}{dx} x + \frac{df(0,0)}{dy} y + \frac{1}{2} \frac{d^2f(0,0)}{dx^2} x^2 +\frac{1}{2} \frac{d^2f(0,0)}{dy^2}y^2  + \frac{d^2f(0,0)}{dydx} x*y

So let's find all the terms:

Remember that:

\frac{dsin(ax)}{dx}  = a*cos(ax)

\frac{dcos(ax)}{dx} = -a*cos(ax)

f(0,0) = sin(0*0) = 1.

\frac{df(0,0)}{dx}*x = y*cos(0*0)*x = x*y

\frac{df(0,0)}{dy} *y = x*cos(00)*y = x*y

\frac{1}{2} \frac{d^2f(0,0)}{dx^2}*x^2 =  -\frac{1}{2}  *y^2*sin(0*0)*x^2 = 0

\frac{1}{2} \frac{d^2f(0,0)}{dy^2}*y^2 =  -\frac{1}{2}  *x^2*sin(0*0)*y^2 = 0

\frac{d^2f(0,0)}{dxdy} x*y = (cos(0*0) -x*y*sin(0*0))*x*y = x*y

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

6 0
3 years ago
Sarah has 50 problems to doon her homework. She completes 25 of her math problems. She has 25 left. When she gets home from scho
nikklg [1K]
She will have 12 math problems. But, unless she does half of a problem, she will have 12 and a half. @[email protected]
4 0
3 years ago
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