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emmainna [20.7K]
3 years ago
14

Need help please! (5^3)^6

Mathematics
2 answers:
Alecsey [184]3 years ago
6 0

Answer:

Simplest value of given expression = 5¹⁸

Step-by-step explanation:

Given algebraic equation;

[5³]⁶

Find:

Simplest value of given expression

Computation:

Given fraction [5³]⁶

Using Property of exponents

[Xᵃ]ᵇ = X ᵃ ˣ ᵇ

So,

Using Property of exponents

⇒ [5³]⁶

⇒ 5 ³ ˣ ⁶

⇒ 5¹⁸

Simplest value of given expression = 5¹⁸

Umnica [9.8K]3 years ago
3 0

Answer:

5^{18}=3,814,697,265,625

Step-by-step explanation:

Multiply the exponents

3×6=18

5^{18}

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What is the standard form of five and three hundred fifty two thousands
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7 0
3 years ago
In a shop, two kinds of candies A and B were sold at $2 each and $5 each respectively. Tammy paid at least $75 for 20 candies A
olga55 [171]

Answer:

Exact answer not possible:  See below.

Step-by-step explanation:

The total that Tammy would pay is the sum of 2A and 5B, where A and B are the number of candies costing $2 and $5, respectively.  Therefore:  

2A + 2B = Total Spent

We are told Tammy spent <u>at least</u> $75, which can be written as "Total Spent > $75."

The equation becomes 2A + 5B > 75

Rearranging:  

2A + 5B > 75

2A  > 75 - 5B

A  > (75 - 5B)/2

To find the maximum of the candy A bought, one can try different values of A and B that result in a total of at least $75.  If the amount spent were $75 exactly, a solution would be 35 A (for $70), leaving $5 for 1 candy B.  But we don't know the exact amount.  The problems states "at least $75."  As far as we know, Tammy may have spent $105, $405, $1,005, or even $4,005 (200 A and 1 B).  One cannot pick a maximum simply since the maximum spent is not defined.  The next possible value above $75 would be $77, which represents 36 A and 1 B candies.

6 0
2 years ago
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