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Yakvenalex [24]
4 years ago
7

TDIS - 9/29 Sketch the inverse of each graphed function.

Mathematics
1 answer:
SashulF [63]4 years ago
6 0

Answer:

use a graph

Step-by-step explanation:

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What is the measure of ∠DEG? A) 133° B) 103° C) 77° D) 67°
Lesechka [4]
77° is the answer to your question
7 0
3 years ago
You can use the what of a quadratic equation to determine the number and type of solutions of the equation?
adoni [48]

You can use the <u>determinant</u><u> (square root)</u> of a quadratic equation to determine the number and type of solutions of the equation.

\sqrt{b^{2}-4ac} > 0    → 2 real solutions

  • if \sqrt{b^{2}-4ac} is a perfect square, then rational sol'ns
  • if \sqrt{b^{2}-4ac} is not a perfect square, then irrational sol'ns

\sqrt{b^{2}-4ac} = 0    → 1 real solution (double root)

\sqrt{b^{2}-4ac} < 0    → 2 imaginary(complex) solutions

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4 years ago
Help?????????????????
seraphim [82]

Answer:

yes it does

Step-by-step explanation:

as you can see,

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7 0
3 years ago
a bacteria triples it’s original population in 25 hours (A=3A0). How big will it’s population be in 100 hours
Maru [420]

Answer:

81 times the original size

Step-by-step explanation:

AA0ktA=3A0=?=?=25hours=A0ekt

Substitute the values in the formula.

3A0=A0ek⋅25

Solve for k. Divide each side by A0.

3A0A0=e25k

Take the natural log of each side.

ln3=lne25k

Use the power property.

ln3=25klne

Simplify.

ln3=25k

Divide each side by 25.

ln325=k

Approximate the answer.

k≈0.044

We use this rate of growth to predict the number of bacteria there will be in 100 hours.

AA0ktA=3A0=?=ln325=100hours=A0ekt

Substitute in the values.

A=A0eln325⋅100

Evaluate.

A=81A0

At this rate of growth, we can expect the population to be 81 times as large as the original population.

7 0
3 years ago
You borrowed 59,000 for 2 years at 11% which was compounded annually what total will you pay back
mariarad [96]
Year one, 59,000 + 11% = 65,490
Year two, 65,490 + 11% = 72,693.90
6 0
3 years ago
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