I have to find the area of the figure

wrote an equation for the line. passing through (-5,7) and parallel to the line whise equation is 5x-3y-4=0

xeze [42]

Step-by-step explanation:

5x-3y-4=0---------(1)

Slope = - coefficient of X/ coefficient of y

= -5/(-3)

= 5/3

(x1,y1)= (-5,7)

Equation of the line,

Y-Y1= slope(X-X1)

Y-7= (5/3)×(X-(-5))

Y-7= (5x+25)/3

3y-7=5x+25

5x-3y+32=0 is the required eqn

3 0

3 years ago

Find the horizontal and vertical asymptotes of f(x). f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the

miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* Lets the meaning of vertical and horizontal asymptotes

- Vertical asymptotes are vertical lines which correspond to the zeroes

of the denominator of a rational function

- A horizontal asymptote is a y-value on a graph which a function

approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

then there is a horizontal asymptote at y = leading coefficient of the

numerator ÷ leading coefficient of the denominator

* Lets solve the problem

∵ $f(x)=\frac{6x}{x+2}$

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ The horizontal asymptote can be described by the line y = 6

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ The vertical asymptote can be described by the line x = -2

6 0

3 years ago

Read 2 more answers

Can sum1 answer asap and pls give explanation :)

Tju [1.3M]

Answer:

whats the question

Step-by-step explanation:

?

6 0

3 years ago

Read 2 more answers

Distance from the x-axis is 2

lapo4ka [179]

It would be 2,0 for the x and y

6 0

3 years ago

Find the value of x such that 365 based seven + 43 based x = 217 based 10.

Pepsi [2]

We need to find the base x in the following equation:

$365_7+43_x=217_{10}$

First, lets convert 365 from base 7 to base 10. This is given by

$365_7=3\times7^2+6\times7^1+5\times7^0$

where the upperindex denotes the position of eah number. This gives

$\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}$

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

$43_x=4\times x^1+3\times x^0$

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

$43_x=(4x+3)_{10}$

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

$194_{10}+(4x+3)_{10}=217_{10}$

For simplicity, we can omit the 10 and get

$194+4x+3=217$

so, we can solve this equation for x. By combining similar terms. we have

$197+4x=217$

and by moving 197 to the right hand side, we obtain

$\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}$

Finally, we get

$\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}$

Therefore, the solution is x=5

8 0

11 months ago