Question

Circle O has center (2, 6) and passes through the point P (4, 3). Write the equation of the line that is tangent to circle O at point P
A:y=3/2,x-3
B:y=2/3,x+1/3
C:y=-3/2,x+9
D:y=-2/3x+17/3

Answer 1

Tangent Lines Practice Answers for Honors Geometry

1a) line AD is perpendicular to line BC

1b) if a line is tangent to a circle, then it is perpendicular to the radius at the point of tangency

2) 120°

3) 4.8

4) 253 km

5) y = 2/3x + 1/3

6) the sides of the triangle satisfy the pythagorean theorem, so the angle between the radius and the tangent is a right angle

7) 12 units and 4√7 units, 14 units and 2√15 units

8) 57.5°

9) 78 cm

Answer 2

First, fine the slope of the lines.

m=3-6/4-2
m=-3/2

To find the perpendicular slope of this, find the opposite reciprocal, or 2/3

Use formula y=mx+b to find the equation of this line.

3=(2/3)(4)+b
3=b+8/3
3-8/3=b+8/3-8/3
1/3=b

Now, plug in the values

y=2/3x+1/3, or B