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aniked [119]
3 years ago
9

What is the value of the expression (x-y)2 when x=5 and y=-1

Mathematics
1 answer:
rodikova [14]3 years ago
6 0
(5- -1)2
(5+1)2
6x2
12
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Choose the correct product of (6x − 2)(6x + 2). (1 point)
Vanyuwa [196]
You did not give any choices but this can easily be solved using the FOIL method. 

FOIL stands for First, Outside, Inside, Last. 

In your equation you have (6x-2)(6x+2)
You will multiply the terms that correspond to each letter 

First: Means first terms of each set. In this case 6x and 6x
6x x 6x = 36x^{2} Now you have your first term in the sequence.

Outside: Means terms found in the outside areas of the whole equation, in this case it is 6x and 2
6x x 2 = 12x Now this is the second term

Inside: Means terms found in the inside areas of the whole equation, in this case it is -2 and 6x
-2 x 6x = -12x Now this is your third term

Last: Means the last terms of each set. In this case it is -2 and 2
-2 x 2 = -4  This is your last term

Now you have what you need for your new equation:

36x^{2} + 12x -12x - 4

Because your second and third terms are like terms, you can combine them by doing the operation indicated. 12x-12x = 0 so now you can cancel it out from your equation and your left with:

36 x^{2} - 4 This is your product
6 0
3 years ago
Let f(x) = -20x2 + 14x + 12 and g(x) = 5x - 6. Find f/g and state its domain.
UkoKoshka [18]

Solution

f(x) = -20x^{2} +14x + 12 and g(x) = 5x - 6.

(f/g)(x) = \frac{f(x)}{g(y)}

(f/g)(x) = \frac{-20x^{2}+14x +12 }{5x - 6}

<u>Step 1: </u>Now we have to factorize the numerator.

f(x) = -20x^2 + 14x + 12

Factor out -2, we get

= -2 (10x^2 - 7x - 6)

Now we can factorize 10x^2 - 7x - 6                  

f(x) = -2(2x + 1) (5x - 6)

<u>Step 2: </u>Plug in the factors

(f/g)(x) = \frac{-2 (2x +1)(5x - 6)}{(5x - 6)}

<u>Step 3:</u> Cancel out the common factor (5x - 6) from the numerator and the denominator, we get

(f/g)(x) = -2(2x +1) = -4x -2

Since -4x -2 is linear expression, the domain is all the real numbers.

Therefore, the answer is –4x – 2; all real numbers

Thank you :)

4 0
3 years ago
EASY 10 PTS
ollegr [7]
The solution is: 252. 14x18
7 0
3 years ago
How do you round off 341
SSSSS [86.1K]
You only can if 341 has a decimal of some sorts. other than that, you cannot round it.
4 0
3 years ago
Read 2 more answers
For the following exercises, determine whether the functions are even, odd, or neither.
stealth61 [152]

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$$

6 0
2 years ago
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