Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:


h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
Answer:
49b^2 -36 = (7b -6)(7b +6)
so because there you missed some signs in these wrote choices
hope helped
Step-by-step explanation:
C is the correct answer, -7 is smaller than 7.
<span>sum of the interior angles of a polygon = (n - 2) x 180
</span>hexagon has 6 sides , in this case n = 6
so
(6-2) x 180
= 4 x 180
= 720
answer
<span>c. 720</span>
A is the correct answer to this problem