The volume is 33.5mm^3 (or cubed)
Formula : v = 4/3πr^3 or v = 4 x 3.14 x (r x r x r) <span>÷ 3
</span>
~ 2 x 2 x 2 = 8 (we use 2 because the radius is half of the diameter)
v = 4 x 3.14 x 8 <span>÷ 3 a. Multiply everything together
v = 100.48 </span><span>÷ 3 b. Divide by 3</span><span>
v = 33.493 c. Round (if needed)
</span>v = 33.5
Step-by-step explanation:
Since it is asking for a perpendicular line, we take the reciprocal of the slope in the given equation to use as the slope for the perpendicular line.
In y = x + 2, m = 1. However, for a perpendicular line we flip and multiply by a negative 1.
(Example: If m = 3, we would take the reciprocal of it and it turns into m = -1/3. If m = - 1/4, we would take the reciprocal of it and it turns into m = 4.)
So, the m = 1 turns into a m = -1.
Now, you can use the point (4,-1) to form a point-slope equation first.
y-(-1) = -1(x-4)
Then, use basic algebra to form a slope-intercept form equation.
y + 1 = -x + 4
y = -x +3
Answer:
r =29.82
Step-by-step explanation:
r/7.1 = 4.2
Multiply each side by 7.1
r/7.1 *7.1 = 4.2*7.1
r =29.82
Step-by-step explanation:
10 2/3 + 3 1/3 = 10 + 3 + 2/3 + 1/3 = 13 + 3/3 = 13 + 1 = 14
Since it is not perfectly straight it’s not linear so
*nonlinear association
The line goes down not up so it’s
*negative association
If your teacher wants to count the point outside of the regular line it would be no association
The two that most fit this graph are nonlinear and negative association
