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3 years ago

30 POINTS! Answer These Algebra 1 Questions ASAP!

Mathematics

2 answers:

MAXImum [283]3 years ago

6 0

What is the question

maksim [4K]3 years ago

5 0

Comment the questions and I’ll attempt them

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Help! I'm a little stumped when it comes to variables in matrices. An explanation would be super rad!

iris [78.8K]

Answer:

Step-by-step explanation:

To find the determinant of a 3x3 matrix, you can use this method. (See picture.)

Start with the first number in the top row, and block off the row and column. A 2x2 matrix will be left. Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.

Repeat for the other two numbers in the top row. Add the first result, subtract the second, and add the third.

det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]

det A = -2 (3)(-5) − 0 + 0

det A = 30

8 0

2 years ago

Please help, the brainiest will go to the one with a good answer.

Mashutka [201]

Option c is your answer 3xy + 7x4

3 0

2 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

1 year ago

Read 2 more answers

What are the solutions of 64x^3 - 1 = 0 by factoring

fenix001 [56]

Answer:

x=1/4

Step-by-step explanation:

7 0

2 years ago

Which function has the same y-intercept as the function y equals 2/3 x - 3

aleksley [76]

We have the function $y = \frac{2}{3} x -3$ and we want to find a function that has the same y-intercept than the previous function.

First, let's find the y-intercept by subtituting 0 for 'x'.

$y = \frac{2}{3} (0) -3 = -3$

Now that we found that y-intercept =-3, any lineal function of the type: $y = ax - 3$ will have the same y-intercept. Where 'a' can take all the real values.

Also, any quadratic function of the type: $y=ax^{2} + bx - 3$ will have the same y-intercept. Where 'a' and 'b' can take all the real values.

6 0

3 years ago