Answer:
Step-by-step explanation:
Answer:
The value in box of circle B is 3 and the value in box which belongs in both circle B and S is 6 and value which belongs in circle S is 1 and the value of box outside both the circle is 2.
Step-by-step explanation:
In given Venn diagram
ε = class of 12 pupils
pupils who have brother B = 9
pupils who have sister S = 7
pupils who have neither brother nor sister = 2
Hence the Venn diagram is drawn in the attachment for your reference.
n(E) =12
n(neither B nor S) = 2
So, n(B or S)= n(E) - n(neither B nor S)= 12-2=10
n(B) = 9
n(S) = 7
Now, addition theorem,
n(B or S) = n(B) + n(S) - n(B and S)
So the value in box which is in both circle B and S is 6.
So the Box which contains only brothers = n(B) - n(B and S) = 9 - 6 = 3
Value in box of circle B is 3.
So the Box which contains only Sisters = n(S) - n(B and S) = 7 - 6 = 1
Value in box of circle S is 1.
Answer:
a.) y = 3/(2ˣ)
b.) y = 1/(2ˣ)
c.) y = (π^π)ˣ
d.) y = (1/27)(1/√(3))ˣ
e.) y = .002908/(.119025ˣ)
f.) y = .00000004808/(.0413ˣ)
Step-by-step explanation:
Concept need to know is:
- a negative exponent will flip the numerator with the denominator
- a fraction as an exponent is just a root. so if the exponent is x^(1/2) then the root is 2 and x^(1/3) is a cube root
- adding and subtracting exponent is the same thing as multiplying the same base.
- so x^(1+2) = (x^1)(x^2)
- and x^(1-2) = (x^1)(x^-2)