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netineya [11]
3 years ago
6

Give the new coordinates. Square WXYZ with vertices W(1,7), X(6,5),

Mathematics
1 answer:
liubo4ka [24]3 years ago
4 0

Given:

The vertices of square WXYZ are W(1,7), X(6,5),  Y(4,0), and Z(-1, 2).

Consider the rule of transformation is (x, y)\to (x-7, y-6).

To find:

The new coordinates.

Solution:

We have,

(x, y)\to (x-7, y-6)

Using the above rule of transformation, we get

W(1, 7)\to W'(1-7, 7-6)=W'(-6,1)

X(6, 5)\to X'(6-7, 5-6)=X'(-1,-1)

Y(4, 0)\to Y'(4-7, 0-6)=Y'(-3,-6)

Z(-1, 2)\to Z'(-1-7, 2-6)=Z'(-8,-4)

Therefore, the new vertices are W'(-6,1), X'(-1,-1), Y'(-3,-6) and Z'(-8,-4).

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Find the point slope equation of the line using the point (6,9) and slope of 3/2
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y=1.5x

Step-by-step explanation:

Use the equation y-y1=m(x-x1)

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7. Are the ordered pairs below an arithmetic sequence or geometric
DochEvi [55]

Answer:

8. Arithmetic Progression

9. f(9) = 300

Step-by-step explanation:

Given

\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3

This gives:

d = 45 - 55 = 35 - 45 = 25 - 35

d = -10 = -10 = -10

d=-10

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<em></em>

Solving (8):

f(n) = f(1) + f(n-1)

To find f(9), we substitute 9 for n

f(9) = f(1) + f(9-1)

f(9) = f(1) + f(8)

We need to solve for f(8); substitute 8 for n

f(8) = f(1) + f(8 - 1)

f(8) = f(1) + f(7)

We need to solve for f(7); substitute 7 for n

f(7) = f(1) + f(7 - 1)

f(7) = f(1) + f(6)

We need to solve for f(6); substitute 6 for n

f(6) = f(1) + f(6 - 1)

f(6) = f(1) + f(5)

We need to solve for f(5); substitute 6 for n

f(5) = f(1) + f(5 - 1)

f(5) = f(1) + f(4)

From the function, f(4) = 25 and f(1) = 55.

So:

f(5)=55 + 25

f(5)=80

f(6) = f(1) + f(5)

f(6) = 55 + 80

f(6) = 135

f(7) = f(1) + f(6)

f(7) = 55 + 135

f(7) = 190

f(8) = f(1) + f(7)

f(8) = 55 + 190

f(8) = 245

f(9) = f(1) + f(8)

f(9) = 55 + 245

f(9) = 300

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