How do you write a rule for 2, 10, 5, 250? Order of operations?
1 answer:
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Well, you could assign a letter to each piece of luggage like so...
A, B, C, D, E, F, G
What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.
My answer and workings are below...
35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.
210 arrangements (35 x 6) when order is taken into consideration.
*There are 6 ways to configure 3 letters.
Alternative way to solve the problem...
Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.
A, B, C, D, E, F, G
What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.
My answer and workings are below...
35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.
210 arrangements (35 x 6) when order is taken into consideration.
*There are 6 ways to configure 3 letters.
Alternative way to solve the problem...
Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.
Laura's age is 9 years.
Solution:
Let x be the age of April.
Laura's age = 2 years more than half of April's age
<u>Convert statement into algebraic expression:</u>
Half of April's age =
2 years more than half of April's age =
Combined age of April and Laura = 23
⇒ April's age + Laura's age = 23
To add the fractions make the denominators same.
Multiplying 2 on both numerator and denominator of unlike terms, we get
Denominators are same, now add the fractions.
Do cross multiplication.
Aprils's age = 14 years
Laura's age =
= 7 + 2
Laura's age = 9
Hence Laura's age is 9 years.