Answer:

Step-by-step explanation:
Given
Sample Size = 2500
Percentage = 30%
Required
Calculate Mean of Y
Mean or Expected Value is calculated as thus;

Where E(Y) represents the mean
n represents the sample size (or population)
p represents the success probability
%

So,


Hence, the mean value of Y is 750
Put 4/2 that's the answer
Answer:
The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the mean subtracted by M. So it is 4.1 - 0.07 = 4.03 pounds
The upper end of the interval is the mean added to M. So it is 4.1 + 0.07 = 4.17 pounds
Rounded to one decimal place
The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.
Step-by-step explanation:
First you divide the numerator and the denominator by 10, it leaves you with 1500/21 , now you again divide the numerator and denominator by 3 and you get 500/7.
Remember, you ought to divide the numerator and the denominator only by the numbers which are their common factors or in a more easier way, you only divide them by a number which divides them both simultaneously.
Answer:
i pretty sure i do not know that answer to be honest
Step-by-step explanation:
i believe this because i dont know anything about this im still lost