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iVinArrow [24]
3 years ago
12

Vanderbilt University has this data set: 305, 315, 285, 285, 290, 280, 300, 310, 310, 315, 305

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:

300

Step-by-step explanation:

305

305 + 305 + 315 + 315 + 285 + 285 + 310 + 310 + 290 + 280 + 300 = 3300 \div 11

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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
masya89 [10]

Answer:

a) There is a 100% probability that the (sample) average time waiting in line for these customers is less than 10 minutes.

b) There is a 100% probability that the (sample) average time waiting in line for these customers is between 5 and 10 minutes.

c) There is a 0% probability that the (sample) average time waiting in line for these customers is less than 6 minutes.

d) Because there are less observations, it would be less accurate.

e) Because there are moreobservations, it would be more accurate.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. This means that \mu = 8.2, \sigma = 1.5.

Suppose that a random sample of n = 49 customers is observed

This means that s = \frac{1.5}{\sqrt{49}} = 0.21.

(a) Less than 10 minutes.

This probability is the pvalue of Z when X = 10. So:

Z = \frac{X - \mu}{s}

Z = \frac{10 - 8.2}{0.21}

Z = 8.57

Z = 8.57 has a pvalue of 1.

This means that there is a 100% probability that the (sample) average time waiting in line for these customers is less than 10 minutes.

(b) Between 5 and 10 minutes.

This probability is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 5.

From a), we have that the zscore of X = 10 has a pvalue of 1.

For X = 5.

Z = \frac{X - \mu}{s}

Z = \frac{5 - 8.2}{0.21}

Z = -15.24

Z = -15.24 has a pvalue of 0.

Subtracting, we have that there is a 100% probability that the (sample) average time waiting in line for these customers is between 5 and 10 minutes.

(c) Less than 6 minutes.

This probability is the pvalue of Z when X = 6. So:

Z = \frac{X - \mu}{s}

Z = \frac{6 - 8.2}{0.21}

Z = -10.48

Z = -10.48 has a pvalue of 0.

This means that there is a 0% probability that the (sample) average time waiting in line for these customers is less than 6 minutes.

(d) If you only had two observations instead of 49 observations, would you believe that your answers to parts (a), (b), and (c), are more accurate or less accurate? Why?

The less observations there are, the less acurrate our results are.

So, because there are less observations, it would be less accurate.

(e) If you had 1,000 observations instead of 49 observations, would you believe that your answers to parts (a), (b), and (c), are more accurate or less accurate? Why?

The more observations there are, the more acurrate our results are.

So, because there are moreobservations, it would be more accurate.

8 0
3 years ago
A car dealership offers a special interest rate of 3.5%. What is 3.5% written as a decimal? A. 0.0035 B. 0.035 C. 0.35 D. 35.0
wel
Make 3.5% out of 100: \frac{3.5}{100} 3.5÷100=0.035. So the Answer is B. 0.035.
7 0
3 years ago
Let the vector v have an initial point at (3,−2) and a terminal point at (3,−7). Determine the components of vector v
kiruha [24]

Answer:

(0,-5)

Step-by-step explanation:

Terminal minus initial. (3-3, -7+2) = (0,-5)

3 0
2 years ago
Read 2 more answers
Another One I need help withhhh sorrry
Effectus [21]

Answer:

y = 2x+3

Step-by-step explanation:

Sorry I'm probably too late since Quizziz doesn't wait unless you have the freeze timer thing.

y = mx+b

b is the y intercept. The y intercept (when x=0) is given in the table.

Now plug a coordinate in to solve for m.

My coordinates: (1,5)

5 = m + 3

Solve.

2 = m

m = 2

Note: never plug in the y intercept when looking for m.

You can also find the slope by (subtracting the y value of one coordinate from another y value of another coordinate)/(subtracting x value from the first y coordinate above from the x value from the second coordinate).

In this case, it'd be

m = (7-5)/(2-1)

m = 2/1

m = 2

6 0
3 years ago
The area of a rectangle is 91 square inches. If the length of the rectangle is 1 less than twice its width, write an equation th
Ahat [919]

The following equation can be used to calculate the width, w, of the rectangle with the specified area: 2w²- w - 91 = 0.

<h3>What is a Rectangle's Area?</h3>

rectangle area = length width

Multiply the length by the width to obtain the area of a rectangle. The formula is as follows: A = L * W where A is the area, L denotes the length, W denotes the width, and * denotes multiplication. where A denotes area, s denotes side length, and implies multiply.

Given,

Rectangle area = 91 in.

2 w = width

The rectangle's length equals 2w - 1.

Using the area formula, the equation for calculating w would be: (2w - 1)(w) = 91.

2w² - w - 91 = 0

As a result, the equation for determining the width, w, of the rectangle with the specified area is: 2w² - w - 91 = 0.

To know more about area, visit:

brainly.com/question/20693059

#SPJ1

5 0
1 year ago
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