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algol [13]
2 years ago
15

Please help me with this guys and it select all that apply

Mathematics
1 answer:
Pie2 years ago
4 0
It’s going to be Bottom 2
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In a right triangle, the side opposite a 33 degree angle is 17 units. What is the length of the side adjacent to that angle to t
AnnyKZ [126]

Answer:

The length of the side adjacent to that angle  is 26 units

Step-by-step explanation:

We are given

In a right triangle, the side opposite a 33 degree angle is 17 units

Firstly, we will draw diagram

we can use trig

cot(33)=\frac{x}{17}

now, we can solve for x

x=17\times cot(33)

x=26.177

So,

The length of the side adjacent to that angle  is 26 units

6 0
3 years ago
Write 4^6 as a power of 2.
Nesterboy [21]
4^6= 24
24 power 2=24x24= 576
6 0
2 years ago
Read 2 more answers
Whoever answers right I’ll give you Brinley
Aleks [24]

Answer:

correct answer B.

Step-by-step explanation:

hoped i helped :) can u mark brainiest pls!!

5 0
3 years ago
Need help anything helps thanks
yKpoI14uk [10]

A binomial squared is written like

x^2+2ax+a^2

So, we have 2a=6 \iff a=3

So, we want to complete the square (x+3)^2 = x^2+6x+9

We can add and subtract 9 to write

x^2+6x = x^2+6x+(9-9) = (x^2+6x+9)-9 = (x+3)^2-9

5 0
3 years ago
A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

7 0
3 years ago
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