Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
The answer is c mean = median
Answer: y=-1x+5
Step-by-step explanation:
1. Use slope-intercept formula (y = mx + b) to find the slope which is represented by the variable 'b'.
m = ∆y / ∆x
m = -1 / 1
m = -1
y= -1x + b
2. Use any cooresponding x and y values to substitute into the formula. Ex: (x,y) → (1,4)
y = mx + b
4 = -1(1) + b
4 = -1 + b
5 = b
3. Plug in the values found into the formula.
y = -1x + 5
Answer:
-25
Step-by-step explanation:
Just divide -125 with 5 to get the answer(-25)
Answer: -7 = q
Step-by-step explanation:
