Let x be a random variable representing the price of a Congo-imported black diamond. Let the higher price be p. Then,
P(x < p) = P(x < (p - mean)/sd) = P(x < (p - 60,430)/21,958.08) = P(z < 2)
Therefore,
(p - 60,430)/21,958.08 = 2
p - 60,430 = 2 x 21,958.08 = 43,916.16
p = 34,916.16 + 60,430 = 104.346.16
Therefore, The required price is $104,346.16
Answer:
8, 13, 18
Step-by-step explanation:
Its adding 5 each time so it ends up at positive values all the way up to 18
1) Change radical forms to fractional exponents using the rule:The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>
![\sqrt[n]{3} = 3^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B3%7D%20%3D%20%20%203%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D)
.
The square root of 3 (

) = 3 to the one-half power (

).
The 5th root of 3 (
![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
) = 3 to the one-fifth power (

).
2) Now use the product of powers exponent rule to simplify:This rule says

. When two expressions with the same base (a, in this example) are multiplied, you
can add their exponents while keeping the same base.
You now have

. These two expressions have the same base, 3. That means you can add their exponents:
3) You can leave it in the form
or change it back into a radical ![\sqrt[10]{3^7}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B3%5E7%7D%20)
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Answer:
or
-1.6 - 0.3
I hope this hepled you and that the answer is correct