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3 years ago

Please help and is #2 right?????

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

7 0

Yes 2 is right I can't see 4

Rudiy273 years ago

4 0

Number two is quadrant 3 if you look up quadrants on a graph it will show you where each quadrant is. You can use this website symbolab for number 3.
You can use Desmosgraphing for number 4

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A postage stamp is shaped like a rectangle with a perimeter of 88 millimeters. The length (x) is 10 millimeters less than twice

Oxana [17]

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4 years ago

at a putt-putt golf course there are 50 yellow golf balls, 45 red golf balls and 65 blue blue golf balls. What ratio compares th

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3 years ago

It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains

sdas [7]

Answer:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

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3 years ago

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Karo-lina-s [1.5K]

Answer:

Y=-2/3x + 5

Step-by-step explanation:

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3 years ago

What is the reciprocal of 7/12

Galina-37 [17]

Answer:

12/7

Step-by-step explanation:

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3 years ago

Read 2 more answers