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3 years ago

Please help and is #2 right?????

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

7 0

Yes 2 is right I can't see 4

Rudiy273 years ago

4 0

Number two is quadrant 3 if you look up quadrants on a graph it will show you where each quadrant is. You can use this website symbolab for number 3.
You can use Desmosgraphing for number 4

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Which of the following values for x and y make the equation 4x+2y+3=19 true?

Aleksandr-060686 [28]

Answer:

x = 3, y = 2

Step-by-step explanation:

Substitute the values of x from each alternative in the previous question, then solve for y. This is depicted below.

A. y = -7, x = 5, 4(5) + 2y + 3 = 19
B. y = 0 and x = 4, 4(4) + 2y + 3 = 19
C. y = 2 and x = 3, 4(3) + 2y + 3 = 1
D. y = 4, x = 2, 4(2) + 2y + 3 = 19

Only the third option has a y value that is comparable to the value in the computations, according to the calculations.

As a result, the letter C is the correct response.

7 0

2 years ago

A family spends 520 every month on food. If the family income is 3,200 each month, what percent of the income is soent on food?

Julli [10]

Answer:

16.25%

Step-by-step explanation:

520/3200 = 52/320 = 16.25%

6 0

3 years ago

M <2=x+94 what does x equal

Shtirlitz [24]

This is as far as I could get X=-94+m<2

6 0

3 years ago

2 less than 7 times a number c is written as

sammy [17]

Answer:

7c-2

Step-by-step explanation:

7 times a number c tells us that we want to multiply c by seven. 2 less than tells us that we want to subtract 2 from 7c.

7 0

2 years ago

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

2 years ago