The graph of the piecewise function includes
(1) a straight line passing through point (-3, 0) and stopping at point (0, 3) with an unshaded small circle at the end of point (0, 3) and an arrow at the other end.
(2) a shaded small circle at point (0, 5), and
(3) a straight line starting at the point (0, -1) and passing through the point (2, 3) with an unshaded small circle at the point (0, -1) and an arrow at the other end.
(-2,6) (5,-8)
slope = (y2 - y1) / (x2 - x1)
slope = (-8 - 6) / (5 - (-2) = -14/7 = -2 <==
midpoint = (x1 + x2)/2 , (y1 + y2)/2
m = (-2 + 5)/2 , (6 - 8)/2
m = (3/2, -1) <===
distance = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((5 - (-2)^2 + (-8 - 6)^2)
d = sqrt ((5 + 2)^2 + (-14^2))
d = sqrt (7^2 + 14^2)
d = sqrt (49 + 196)
d = sqrt 245
d = 15.65 <==
Answer:
-7.5x3+(20+2.5)=0
this one is equal to 0 ;)
Answer:
The new points after dilation are
(3/2, -3) and (9/2,-3)
Step-by-step explanation:
Here in this question, we want to give the new points of the line segment after it is dilated by a particular scale factor.
What is needed to be done here is to multiply the coordinates of the given line segment by the given scale factor.
Let’s call the positions on the line segment A and B.
Thus we have;
A = (1,-2) and B = (3,-2)
So by dilation, we multiply each of the specific data points by the scale factor and so we have;
A’ = (3/2, -3) and B’= (9/2,-3)
