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DedPeter [7]
3 years ago
5

The time that a butterfly lives after emerging from its chrysalis can be modelled by a random variable T, the model here taking

the probability that a butterfly survives for more than t days as P(T>t)=36(6+t)2, t≥0. For these problems, please ensure your answers are accurate to within 3 decimals. Part a) What is the probability that a butterfly will die within 6 days of emerging? 0.75 Part b) If a large number of butterflies emerge on the same day, after how many days would you expect only 6 % to be alive? 18.494 Part c) Calculate the mean lifetime of a butterfly after emerging from its chrysalis?
Mathematics
1 answer:
olasank [31]3 years ago
8 0
Xd answer is d I hope u find the answer
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What is the answer to 16-2t = t + 9 + 4t <br><br>I need it now
bogdanovich [222]

16 - 2t = t + 9 + 4t

16 - 2t = 5t + 9

-7t = -7

t = 1

Hope this helps! ;)

5 0
3 years ago
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Please help. NO LINKS. ​
trasher [3.6K]

Answer:

the answer is A

y= 1.9x + 69

y=6x

5 0
3 years ago
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Zinaida [17]
Answer: -29a-6b+59c
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6 0
3 years ago
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(20 PTS)<br> 4x-(3x-2x)=3(2x-1) <br> A. 0<br> B. 1<br> C. Infinitely Many
Mkey [24]

4x-(3x-2x)=3(2x-1)

4x - 3x + 2x = 6x - 3

3x = 6x - 3

-3x = - 3

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3 0
3 years ago
Quadratic equation
Murrr4er [49]

Answer:

<h2>            46</h2>

Step-by-step explanation:

x          -  age of a son three years ago

3x        -  age of a father three years ago

x + 3      -  age of the son now

3x + 3       -  age of the father now

x + 3 + 5       -  age of the son in five years time

3x + 3 + 5       -  age of the father in five years time

in five years time, the father will be twice as old as his son, so:

3x + 3 + 5 = 2(x + 3 + 5)

3x + 8 = 2x + 16

3x - 2x = 16 - 8

  x = 8

x + 3 + 4       -  age of the son in four years time

8 + 3 + 4 = 15

3x + 3 + 4       -  age of the father in four years time

3×8 + 3 + 4 = 31    

the sum of their ages in four years time:

15 + 31 = 46

8 0
3 years ago
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