Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)
Answer:
Step-by-step explanation:
Notice that we are in the presence of an arithmetic sequence (there is a common difference of 6 between a term and the next). So thisis an arithmetic sequence with first term 
. and common difference "<em>d</em>" = 6.
Recall now the formula for the nth term (
) of an arithmetic sequence:
Then, using our values in the formula, we get:
In this case, i think you just need to divide the amount of telephone subscription and divide it among 100 people
For example, let's say that there is around 2,000,000 subscription for 100,000 users.
The amount would be : 2,000,000 / 1,000
= 2,000 number of mobile per 100 people
hope this helps
