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3 years ago

8

The high temperature for the day was 13 degrees F. The difference between the high and low temperature was 16 degrees F. What wa

s the low temperature?

1 answer:

kakasveta [241]3 years ago

8 0

Answer:

the answer is 29 degrees F i am a you tuber please subscribe to nikolys on you tube

Step-by-step explanation:

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Can someone help me with these 3 questions of you can and show the work too

Vesnalui [34]

Hi
1. Temp was 5 at noon and dropped 59 degrees at midnight. 5+(-59)= -54 (B)

2. The stock dropped by 5 points and opened at 93 points that day.
93+(-5)=88 points (B)

3. The temperature fell by 12° over 4 hours.
12÷4=3° decreased per hour (C)

Hope that clarifies these. Let me know if these aren't clear.

5 0

3 years ago

8. It is a 575 mile drive to El Paso from Austin. A map scale shows that 5 centimeters is

Nezavi [6.7K]

Answer:

23 cm

Step-by-step explanation:

575/25=23

5 0

3 years ago

1. Find the vertices and locate the foci for the hyperbola whose equation is given.

Irina18 [472]

$\bf \cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})\\\\
-----------------------------\\\\
\textit{now let's take a look at yours}
\\\\\\
49x2 - 16y2 = 784\implies \cfrac{49x^2}{784}-\cfrac{16y^2}{784}=1
\\\\\\
\cfrac{x^2}{16}-\cfrac{y^2}{49}=1\implies \cfrac{(x-0)^2}{4^2}-\cfrac{(y-0)^2}{7^2}=1
\\\\\\
recall\implies center\ ({{ h}},{{ k}})\qquad vertices\ ({{ h}}\pm a, {{ k}})
\\\\\\
$

$\bf \textit{now, for the foci, the foci are "c" distance from the center point}\\\\\
whereas\qquad c=\sqrt{a^2+b^2}\qquad \textit{ that is }\qquad h\pm \sqrt{a^2+b^2}$

notice your "a" and "b" components, to get the distance "c" from the center to either foci and the vertices, of course, are h + a, k and h - a, k

5 0

3 years ago

5 yards 2 feet × 2=

klio [65]

Answer:

11 1/3 yards or 34 feet

6 0

4 years ago

Read 2 more answers

Marie scored 95,86 and 89 on three science tests. She wants her average score for 6 tests to be at least 90. What inequality can

aliya0001 [1]

270+3s>=540. i did the math and I'm pretty sure this is the correct answer

5 0

4 years ago