False.
y= 3(1)+1= 4
y= 3(2)+1=7 not 5
y= 3(3)+1=10 not 6
Check whether it is possible to have a triangle with the given side lengths for example 7,9,13 then add any two sides and see if it is greater than the other side. Example the sum of 7 and 9 is 16 and 16 is greater than 13
Step-by-step explanation:
so, if I understand this correctly, the original square had a side length of 8 m.
now we transform this square into one with side length 1/4×8 = 8/4 = 2 m.
and the questions are what are the perimeter and the area of that new (smaller) square ?
the perimeter of a square is
4× side length = 4×2 = 8 m
the area of a square is
side length ² = 2² = 4 m²
Tangent always meets radius at 90° angle.
Angle ABC = 90° so Pythagoras' theorem applies.
r² + 4² = (r+2)²
r² + 16 = r² + 4r + 4
12 = 4r
r = 3
