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Troyanec [42]
3 years ago
5

OMG!!??!!?? SCIENTISTS TRANSFORM 6IX9INE INTO A RAT?!??????!!?! LOOK AT HIM!!!!!!!!​

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
OMG !!!?!?!?! IS IT REAL
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What are three 2-digit numbers that divide into 1520?
vlada-n [284]
1520 ÷ 10 = 152

1520 ÷ 20 = 76

1520 ÷ 40 = 38
7 0
3 years ago
You want to give your friend a soccer ball for a gift. The soccer ball has a
Ede4ka [16]

Answer:

volume of cube share box = 67.92 inch²

Step-by-step explanation:

given data

soccer ball volume = 85.3π cubic inches

solution

we know that ball will fit inside the box when box length will be equal to diameter of ball

and here soccer ball volume will be express as

soccer ball volume = \frac{4}{3}\times \pi \times r^3      .................1

85.3π  =  \frac{4}{3}\times \pi \times r^3    

solve it we get

r³ = 69.9765

r = 4.12 inch

so diameter = 2 × 4.12 = 8.24 inch

diameter = length of box side

volume of cube share box = a²

volume of cube share box = 8.24²

volume of cube share box = 67.92 inch²

6 0
3 years ago
If the statement is e is the midpoint of df what is the reason
Katena32 [7]

For E to be the midpoint of DF, it needs to divide DF in 2 equal segments, DE and EF. If E is the midpoint of DF, then DE and EF are equal, so the reason is that the expressions for DE and EF are equal. The reason is:

6x+5=8x-1

3 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. It forms a pile in the shape of a right circu
Sunny_sXe [5.5K]

Answer:

0.0221 feet per minute.

Step-by-step explanation:

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

Rate of Change of the Volume, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Since gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. Therefore, the Volume of the cone is increasing at a rate of 10 cubic feet per minute.

\dfrac{dV}{dt}=10$ ft^3/min

We want to determine how fast is the height of the pile is increasing when the pile is 24 feet high.

We have:

\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10\\\\$When h=24$ feet$\\\dfrac{3\pi *24^2}{12}\dfrac{dh}{dt}=10\\144\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{144\pi}\\ \dfrac{dh}{dt}=0.0221$ feet per minute

When the pile is 24 feet high, the height of the pile is increasing at a rate of 0.0221 feet per minute.

4 0
3 years ago
Which of the following functions would result in a graph that is shifted three units to the left of g(x) = 4logx
Ber [7]
Replace the x by x+3

so it would be
4log(x+3)
4 0
3 years ago
Read 2 more answers
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