Answer:
Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.
Step-by-step explanation:
For the $200, the restocking fee is $12, so the ratio of the restocking fee to the price of the item is 12/200.
For the $150, the restocking fee is $9, so the ratio of the restocking fee to the price of the item is 9/150.
Now we find out if the ratios 12/200 and 9/150 are equal.
12/200 = 3/50
9/150 = 3/50
Both ratios reduce to the same ratio 3/50, so the restocking fee is proportional.
Add half a tenth.
.. 4.9675 +0.05 = 5.0175
Throw away all the digits to the right of the tenths digit.
.. 5.0
Your rounded number is 5.0
Answer:
If it's not too late by now, the answer is 19.9 
Answer:
The line segment partitioned two-fifths from A to B is (10,6)
Step-by-step explanation:
First point from A to B is (16,8)
than find the difference between A to B i.e B - A
(1,3)-(16,8) = (-15,-5)
To measure the (2/5) difference we will multiply (-15,-5) with (2/5) which is equal to (-6,-2)
Now Add the difference to the first coordinate (point A) gives
Point of division = (16,8)+(-6,-2)
Point of division = (16-6, 8-2)
Point of division = (10,6)
Answer:
a) 
b) ![P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5B0.0211%2B0.0995%2B0.211%5D%3D0.668)
c) 
Step-by-step explanation:
1) Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
2) Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part a
Part b
![P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5BP%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29%5D)
Part c
