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Anon25 [30]
3 years ago
11

ANSWER ASSAPP !!!!!!!!!!!!

Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

A: 11,13, 290

B: 7,24,25

Step-by-step explanation:

A &B both form a right triangle not C

You might be interested in
How do i put y= 75x +1,200 in standard form into Ax+ By=c
Anarel [89]

Answer:

-75x + y= 1,200

Step-by-step explanation:

subtract 75x to move to the other side. canceling it out and moving it to the left. it becomes -75x + y and leaving 1,200 alone.

7 0
3 years ago
QUESTION 9 Imagine that the mean height for all Division I women's basketball programs is 69 inches with a standard deviation of
fenix001 [56]

Answer:

98.98% of means would fall below that for these UConn Huskies

Step-by-step explanation:

To solve this qustion, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = 3, n = 10, s = \frac{3}{\sqrt{10}} = 0.9487

The 2010–2011 women's basketball team at the University of Connecticut, with 10 players listed on the roster, had an average height of 71.2 inches. Using the z statistic, what percent of means would fall below that for these UConn Huskies?

This is the pvalue of Z when X = 71.2. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{71.2 - 69}{0.9487}

Z = 2.32

Z = 2.32 has a pvalue of 0.9898

98.98% of means would fall below that for these UConn Huskies

3 0
3 years ago
If a toy store sold four times as many dolls then trucks and dolls cost $24 each and trucks cost $17 each and they sold $1469 wo
expeople1 [14]

Answer:

13 trucks & 52 dolls

Step-by-step explanation:

Let number of trucks sold be t

and

number of dolls sold be d

Since dolls sold were 4 TIMES of trucks, we can write our 1st equation as:

d = 4t

Also, trucks cost 17 and dolls cost 24 and together they sold 1469, so we can write 2nd equation as:

17t + 24d = 1469

Putting 1st equation in 2nd one, we get an equation in "t" and lets solve for t:

17t + 24(4t) = 1469

17t +96t = 1469

113t = 1469

t = 1469/113 = 13

So, 13 trucks were sold

And, now we know d = 4t, so d = 4(13) = 52

So, 52 dolls were sold

6 0
2 years ago
Helpppp<br> Solve for x.
SVEN [57.7K]

Answer:

x = 28.744

Step-by-step explanation:

Seeing as this is a right triangle, and you're given an angle, an unknown measurement to the opposite side, and the measure of the adjacent side. You can use trig functions. In this case, tangent, because you are given the opposite and adjacent, and tangent covers opposite/adjacent.

Tan(32)=x/46

Tan(32)46=x

28.744=x

5 0
2 years ago
It takes 5 cups of flour to bake a loaf of bread. How many loaves can be made with 37 cups of flour?
AleksandrR [38]

Answer:

We can make around 7 loaves of bread with 37 cups of flour.

Step-by-step explanation:

Given that 5 cups of flour to bake a loaf of bread.

i.e.

5 cups of flour = 1 loaf of bread

Thus,

37 cups of flour can be determined by dividing 37 by 5.

37/5 = 7.4

        = 7 loaves of bread   (rounding to the whole number)

Therefore, we can make around 7 loaves of bread with 37 cups of flour.

4 0
2 years ago
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