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AleksandrR [38]
3 years ago
12

30 points. Participant A runs at a slower rate than Participant B. Both participants run at a constant rate. This table represen

ts Participant A. Time (min) 5 8 12 15 Number of laps run 2.75 4.4 6.6 8.25 Which equation could represent Participant B? Time in minutes is represented by x and number of laps run is represented by y. Select each correct answer. y = 0.3x y = 0.9x y = 0.7x y = 0.5x
Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
Participant A runs
2.75 laps in 5 minutes.
2.75/5 = 0.55 lap/minute

If x = minutes, and y = laps, then the equation for Participant A is
y = 0.55x

y = 0.3x and y = 0.5x represent a slower participant than A.

Participant A is slower than Participant B, so Participant B must run faster than Participant A.

y = 0.7x and y = 0.9x represent a faster race that y = 0.55x

Answer:
y = 0.7x
y = 0.9x
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James has a balance of $1,230 on his credit card that has an APR of 24%. He currently pays the minimum monthly payment of
ArbitrLikvidat [17]

Answer:

the answer is B James can eliminate $25 from Food/Clothes and $27 from Entertainment.

hope it helps!

7 0
3 years ago
Tickets prices for a science museum are $18 for adults and $12 for students. If $162 is collected from a group of 12 people, how
riadik2000 [5.3K]
X=number of adults, y= number of students

x+y=12
18x+12y=162

You can simplify the second equation by dividing by six: 3x+2y=27
Rearrange the first equation: y= 12-x. Plug y into the simplified second equation:

3x+2(12-x)=27
3x-2x+24=27
x=3.

Plug the now known x value into y=12-x. So y= 9.
Therefore, there are 3 adults and 9 students.

6 0
4 years ago
Help me please! (Look at image.)
Svetradugi [14.3K]
4^2 = 16
so x must be greater than 16
answer
E. 17
F. 19
8 0
3 years ago
A booster club sells raffle tickets • Before tickets go on sale to the public, 120 tickets are sold to student athletes. • After
GaryK [48]

Answer:

The top graph.

Step by step:

Before the tickets go on sale, 120 tickets were already sold.

After that, the tickets sell at a constant rate for a total of 8 hours.

At the end of this time, all the tickets were sold (we have 0 tickets left)

If x (horizontal axis) represents the hours since tickets go on sale, and y (vertical axis) represents the number of raffle tickets sold.

Then, at x = 0, we should already see y = 120

Because we start with 120 tickets sold.

Then, as x increases, the number of tickets sold also should increase, until we get x = 8 hours, where y stops increasing because all tickets are already sold.

Then we should have an increasing line that stops increasing at x = 8 hours.

Then the correct option is the above graph, where we have:

An increasing line.

y = 120 in the vertical axis (y = 120 when x = 0)

3 0
3 years ago
F(t) = -(t-2) (t-15)
Goryan [66]

Answer:

smaller (t) = 2 and this in coordinates form (2,0)

larger (t) = 15 and this in coordinates form (15,0)

the vertex of the parabola =  (\frac{17}{2} ,\frac{169}{4} ) or in decimals (8.5, 42.25)

Step-by-step explanation:

  • For the zeros of the function take each bracket and make it equal to zero.

SMALLER (t):

(t-2)=0

(add 2 for both sides)

t=2

LARGER (t):

(t-15)=0

(add 15 for both sides)

t=15

  • For the vertex of the parabola you do:

step1: expand the brackets:

f(t)=-(t-2)(t-15)

f(t)= -t^{2} +17t-30

step2: define a,b and c using the expression ax^{2} +bx+c :

a= -1 (the coefficient of t^{2} )

b= 17 (the coefficient of t)

c= -30 (the single number without a letter)

step3: sub the values in the formula -\frac{b}{2a} to find the x coordinate of the vertex :

-\frac{b}{2a}

= - \frac{17}{2*-1}

= \frac{17}{2} or in decimals 8.5

step4: sub the value of t (the x-coordinate) in equation f(t):

f(t)= -t^{2} +17t-30

f ( \frac{17}{2})  = - (\frac{17}{2} )^{2}+ 17× \frac{17}{2} - 30

= -\frac{289}{4} + \frac{289}{2} -30

=\frac{169}{4} or in decimals 42.25

(THIS IS A PICTURE OF THE GRAPH↓)

6 0
3 years ago
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