12 + 0.15m = 10 + 0.25m
0.15m - 0.25m = 10 - 12
- 0.10m = -2
m = -2/-0.10
m = 20
At 20 miles, the cost of the two taxi services will be the same.
Answer:
The rate of change of the distance between the cars at that instant is 5.46 meters per second
Step-by-step explanation:
Speed of first car = 7 m/s
Speed of second car = 3 m/s
At instant, distance of first car from intersection = 5 meters
distance of second car from intersection = 12 meters
Therefore, we have
Distance between both cars at intant = √(12² + 5²) = 13 m
Rate of cahnge of distance is given by;
2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt
= 26dd/dt = 2×5×7 + 2×12×3 = 142
dd/dt = 142/26 = 5.46 m/s.
That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.
Answer:
Percentage of uncertainty=26%
Step-by-step explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.I hope my explanation will help you in understanding this particular question.
