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3 years ago

What is the value of this expression when g=-3.5?

Mathematics

1 answer:

Lady_Fox [76]3 years ago

3 0

Answer:

The value of the expression 8 - I2g - 5I is -4 ⇒ D

Step-by-step explanation:

The absolute value always gives a positive value IaI = a and I-aI = a

Let us solve the question

∵ The expression is 8 - I2g - 5I

∵ The value of g is g = -3.5

→ To find the value of the expression substitute g by -3.5

∵ 8 - I2g - 5I = 8 - I2(-3.5) - 5I

∴ 8 - I2g - 5I = 8 - I-7 - 5I

∴ 8 - I2g - 5I = 8 - I-12I

→ By using the rule above

∵ I-12I = 12

∴ 8 - I2g - 5I = 8 - 12

∴ 8 - I2g - 5I = -4

∴ The value of the expression 8 - I2g - 5I is -4

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Answer:

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8 0

3 years ago

Read 2 more answers

Find the values of x and y, write your answer in simplest form.

tamaranim1 [39]

Answer:

Step-by-step explanation:

You have a 30-60-90 triangle. The sides of a 30-60-90 are in the ratio 1:√3:2.

The side opposite the 30° angle is 5, so the side opposite the 60° angle is 5√3, and the side opposite the 90° angle is 5×2 = 10.

x = 5√3

y = 10

3 0

2 years ago

THE AREA OF A LAKE ON THE MAP IS 12CM SQUARE CALCULATE THE ACTRUAL AREA OF THE LAKE IN KM

den301095 [7]

Answer:

if 1cm is for 1km there are 12km

Step-by-step explanation:

it can depend on the size of the map but if there is a scale which shows how many km per cm then multiply by 12

6 0

2 years ago

Please help I will give brainly

Angelina_Jolie [31]

Answer:

The slope of the line is 2.

This means that Jan runs 2 laps every 1 minute.

4 0

3 years ago

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

dedylja [7]

<u>Answer:</u>

32 units

<u>Step-by-step explanation:</u>

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = $\sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100}$ = 10 units

BC = $\sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16}$ = 4 units

CD = $\sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36}$ = 6 units

AD = $\sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144}$ = 12 units

Perimeter of ABCD = $10+4+6+12$ = 32 units

6 0

3 years ago