Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:
You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
Answer:
The area of the square is 25.
Step-by-step explanation:
In the given square, the length of the side = 5d.
Area of a square = side × side
Given: Side = 5d
Now plug in side 5d in the above area formula, we get
Area of the square = 5d × 5d
= 25
Therefore, the answer is 25.
Answer:
range = 7.87
X = 62.12, X²= 164.3516
mean = 1.2424
variance = 1.779
standard deviation = 1.33379
coefficient of variation = 107.3559%
Step-by-step explanation:
a.) The range =
highest number - lowest number
= 7.89 - 0.02
= 7.87
b.) from the attachment I solved for X and X²
∑X = 62.12
∑X² = 164.3516
c.)
the mean = ∑x/n
n = 50
= 62.12/50
= 1.2424
variance =
σ² = [∑x²-(∑x)²/n] / n-1
= [164.3516 - (62.12)²/50] / 50-1
= 164.3516 - 77.17788/49
= 87.173712/49
= 1.779
standard deviation = √σ
= √1.779
= 1.33379
d. coefficient of variation
= σ/mean * 100
= 1.33379/1.2424 * 100
= 107.3559
This number tells us that the the standard deviation of the time to failure is larger than the average time. option 3 is the correc4 answer here
