Car 1 consumes 30 gallons of gas.Car 2 consumes 20 gallons of gas.
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
Answer:
C.
Step-by-step explanation:
When we add up all the numbers we get 111 then we divide it by 10 which gives us 11.1. since we have no value to round to the tenths place, the answer stays the same.
Remember the arc is equal to the central angle, so ab will equal angle APB. they told you angle APB is a right angle, how many degrees is this? that is what ab will be also:)
The first thing you should observe in the graph is that
6x + 4y = 24 is a line with a negative slope.
2x-4y = -8 is a line with positive slope.
After you identify the functions you can choose the correct affirmations.
The x-coordinate of the solution is 2. The y-coordinate of the solution is 3. The ordered pair that is the solution to the system lies in Quadrant I.
