Unit test

Elan Coil [88]

I will mark brainlist please help

Story : A Dog’s Tale by Mark Twain

1. Using a dog as narrator gives the passage a tone of —

• objectivity
• formality
• bitterness
• humor

2. What literary device is used in the sentence “She had one word which she always kept on hand, and ready, like a life-preserver”?

• Simile
• Metaphor
• Hyperbole
• Onomatopoeia

3. Based on the second paragraph, the word mastiff most likely means —

• a large dog
• a male dog
• a man’s shirt
• a part of a ship

4. According to the author, what would bring such happiness to the dogs as he describes at the end of the story?

• They helped the author’s mother find the words she used, so they especially enjoyed watching her use them.

• They knew the meaning of “supererogation” and realized they were listening to a funny joke.

• Watching and laughing as others were embarrassed vindicated their own previous embarrassment.

• They were generally happy dogs who often expressed a great deal of joy.

5. “A Dog’s Tale” uses the topic of animal communication in order to —
• show how dogs really communicate

• explain how animals learn from humans

• demonstrate that dogs are smarter than most people

• poke fun at human behavior

6. The amount of time that passes during this story is most likely —

• 10 hours

• 10 days

• 10 months

• 10 years

7. An underlying theme in this story is that —

•many people use words without knowing their meanings

• dogs know more than people realize

• family loyalty takes top priority

• strangers are almost always suspicious

8. Since the author used first person, readers are left to wonder —

• how the author felt about his mother

• how strangers reacted to his mother’s word knowledge

• what the author’s mother was thinking

• whether or not the author’s mother knew the meanings of all the words she used

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3 years ago

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$