50 points! I would really like if mhanifa helped... I will mark brainliest
1 answer:
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See the attached picture with letters to better understand the problem
we know that
the figure is a regular hexagon
</span></span>so
in the triangle ABC
BC=2 units
∠ABC=30°
∠BAC=60°
tan 30°=AC/BC
solve for AC
AC=BC*tan 30°-------> AC=2*(√3)/3
<span>Apothem is equal to AC
</span>Apothem=(2/3)√3
the answer is
(2/3)√3
we know that
the figure is a regular hexagon
A regular hexagon has:
<span>Interior Angles of <span>120°</span></span>so
in the triangle ABC
BC=2 units
∠ABC=30°
∠BAC=60°
tan 30°=AC/BC
solve for AC
AC=BC*tan 30°-------> AC=2*(√3)/3
<span>Apothem is equal to AC
</span>Apothem=(2/3)√3
the answer is
(2/3)√3
Answer:
Polynomials of degree 8 have exactly 8 roots
Step-by-step explanation:
The Fundamental Theorem of Algebra states that every polynomial of degree n
with
has exactly n roots.
But the roots may be complex numbers.
In your case n=8, so polynomials of degree 8 have exactly 8 roots.
The roots need not be different.
For example, for the polynomial
x=2 is root twice.