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vichka [17]
3 years ago
7

sam goes to lunch with a friend. the total cost of the lunch is $15 . sam leaves $1.50 as a tip. what percent of total did he ti

p
Mathematics
1 answer:
gavmur [86]3 years ago
7 0
It should be a 10% tip. To simplify the answer, The decimal moves one space (which would be equal to a tenth) so it’s a 10%
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Two ships leave from the same port. One travels west 84 miles and the other travels 62 miles north. Determine the distance betwe
Lerok [7]
The distance the ships traveled are like the legs of a triangle and the question wants to know the hypotenuse. To find the hypotenuse, use the pythagorean theorem. this is a^2 + b^2 = c^2, with a and b being the legs and c being the <span>hypotenuse.
</span>Plug in known values:
84^2 + 62^2 = c^2
Solve:
84^2 = 7056
62^2 = 3844
7056 + 3844 = c^2
7056 + 3844 = 10900
10900 = c^2
Now you just need to isolate c by finding the square root of both sides.
√10900 = 104.403
√c^2 = c

So c = 104.403, or just 104.40 when rounded to the nearest tenth.
And if c is 104.40, then that means the hypotenuse is 104.40.
And all of that basically means that the distance between the ships is 104.40 miles.
5 0
3 years ago
Can someone please help
Rashid [163]

Answer:

It shifted 6 units down

Step-by-step explanation:

Do the graph normally without the k and compare them side by side.

8 0
2 years ago
Find the zeros : x(x^2+13x+40)
Ksju [112]
The zeros are x= 0,-5,-8. the zeros are the x values where the graph intersects the x-axis. to find the zeros, you have to replace y with zero then solve for x.
3 0
3 years ago
A rectangular laboratory tray is 3/5 feet by 7/6 feet. What is the area
Alexus [3.1K]
7/10 is the simplest form of the fraction when you multiply (3/5) by (7/6)
6 0
3 years ago
The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Write and solv
myrzilka [38]

An absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Therefore, the inequality can be written as,

(114.5 - 17.5) lbs < x < (114.5 + 17.5) lbs

97 lbs < x < 132 lbs

Hence, an absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

4 0
2 years ago
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