2x² + 12x + 11 - (x - 4)²
2x² + 12x + 11 - 1(x - 4)²
2x² + 12x + 11 - 1(x - 4)(x - 4)
2x² + 12x + 11 - 1(x(x - 4) - 4(x - 4))
2x² + 12x + 11 - 1(x(x) - x(4) - 4(x) + 4(4))
2x² + 12x + 11 - 1(x² - 4x - 4x + 16)
2x² + 12x + 11 - 1(x² - 8x + 16)
2x² + 12x + 11 + 1(x²) + 1(8x) - 1(16)
2x² + 12x + 11 + x² + 8x - 16
2x² + x² + 12x + 8x + 11 - 16
3x² + 20x - 5
The answer is 7. This is the only number greater than 5.
<span>A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector
of a line segment can be constructed using a compass by drawing circles
centered at and with radius and connecting their two intersections.
Hope i helped
</span>
Answer:
51/25 and 27/4
Step-by-step explanation:
distributing and dividing both sides by coefficient of x
Answer:
(2, 1 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( 
, 
)
Here (x₁, y₁ ) = (7, 3) and (x₂, y₂ ) = (- 3, - 1) , then
midpoint = ( 
, 
) = ( 
, 
) = (2, 1 )
