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AleksandrR [38]
2 years ago
8

Solve: 4x - 8 > 32 A) X <10 B)x > -10 C) X > 10 D) X < -10​

Mathematics
1 answer:
larisa [96]2 years ago
7 0

Answer:

C) x > 10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

4x - 8 > 32

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 8 on both sides:                    4x > 40
  2. Divide 4 on both sides:                x > 10

Here we see that any value <em>x</em> greater than 10 would work as a solution to the inequality.

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Answer:

x =(0,6) y=(0,8)

Step-by-step explanation:

3x+6y=24

make x =0

3(0)+6y=24

6y=24

y=6      x=0

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Which is the graph of the linear equality 2x-3y&lt;12
WINSTONCH [101]

Answer:

The graph below shows the answer to

2x - 3y < 12

Also shown as

-3y < -2x + 12

Step-by-step explanation:

You can rearrange the inequality by subtracting 2x from both sides to isolate the y.

You now have -3y < 12 -2x

which can be put into the standard linear equation form of

-3y < -2x + 12

Then you divide both sides by -3 to get singular value of y, which is something like

-3/-3y < -2/-3x + 12/-3

which is

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Note: I switched direction of the inequality because you are dividing both sides by a negative value.

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We have f(x)=\dfrac{x+5}{3x-1}.

To find inverse function f^{-1}(x) we substitute x with f^{-1}(x) and vice-versa to get

x=\dfrac{f^{-1}(x)+5}{3f^{-1}(x)-1}

Now solve for f^{-1}(x). Note that I will use j instead.

x=\dfrac{j+5}{3j-1} \\x(3j-1)=j+5 \\3jx-x=j+5 \\3jx-x-j-5=0 \\3jx-j=x+5 \\j(3x-1)=x+5 \\j=\dfrac{x+5}{3x-1}

So we find that f(x)=f^{-1}.

Hope this helps.

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