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MaRussiya [10]
1 year ago
14

Which of the following statements are true?

Mathematics
1 answer:
Varvara68 [4.7K]1 year ago
4 0

I and IV only are statements that are true out of all the statements.

<h3>How to solve an equation?</h3>

To solve linear equations, utilize the steps that are provided below.

  1. Remove parentheses from each side of the equation and combine similar terms to make it simpler.
  2. To separate the variable term on one side of the equation, use addition or subtraction.
  3. To find the variable, use division or multiplication.
  4. The common denominator can be multiplied by each side of the equation to eliminate fractions.

Lets take an example of solve z for 7z – (3z – 4) = 12

Here is no multiplication or division, so this will be easy to solve

⇒ 7z – (3z – 4) = 12

⇒ 7z – 3z + 4 = 12

⇒ 4z = 12 – 4

⇒ 4z = 8

⇒ z = 8/4

⇒ z = 2

See, that was so simple, using the mentioned methods, every linear equation can be solved easily.

<h3 />

I. -(-6)=6 and -(-4)>-4

⇒ 6 = 6 and 4 > -4

IV. 17>2 or 6<9

Learn more about  linear equations

brainly.com/question/14323743

#SPJ4

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3 years ago
Mary Grace has 3 more Jolly Ranchers than Isabella. If Isabella has 10 Jolly Ranchers, how many do they have total?
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Please someone help me with this word problem for my math class T.T
olga55 [171]

Answer:

<u>Perimeter</u>:

= 58 m (approximate)

= 58.2066 or 58.21 m (exact)

<u>Area:</u>

= 208 m² (approximate)

= 210.0006 or 210 m² (exact)

Step-by-step explanation:

Given the following dimensions of a rectangle:

length (L) = \sqrt{252} meters

width (W) = \sqrt{175} meters

The formula for solving the perimeter of a rectangle is:

P  = 2(L + W) or 2L + 2W

The formula for solving the area of a rectangle is:

A = L × W

<h2>Approximate Forms:</h2>

In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.  

13² = 169

14² = 196

15² = 225

16² = 256

Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width).  We can use these values to approximate the perimeter and the area of the rectangle.

P  = 2(L + W)

P = 2(13 + 16)

P = 58 m (approximate)

A = L × W

A = 13 × 16

A = 208 m² (approximate)

<h2>Exact Forms:</h2>

L = \sqrt{252} meters = 15.8745 meters

W = \sqrt{175} meters = 13.2288 meters

P  = 2(L + W)

P = 2(15.8745 + 13.2288)

P = 2(29.1033)

P = 58.2066 or 58.21 m

A = L × W

A = 15.8745 × 13.2288

A = 210.0006 or 210 m²

8 0
3 years ago
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