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OlgaM077 [116]
3 years ago
15

3(x-6)-8x=-2+5(2x+1)

Mathematics
1 answer:
GaryK [48]3 years ago
5 0
Answer: x= - 7/5

Explanation:
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Plzzzzzzzzzzzz help me
grigory [225]

Answer:

y=-3/2x+6

Step-by-step explanation:

You can find the slope by taking two points on the graph, and making the one that occurs earlier in the graph (from left to right) the first point (x1, y1) and the one that occurs later in the graph the second point (x2, y2). The equation is m (or slope)=(y2-y1)/(x2-x1). I took the first two points in the table for this. m=(12-18)/-4-(-8)

the double negative on the bottom becomes an addition=> (12-18)/(-4+8)

the top simplifies to be -6 and the bottom simplifies to 4=>-6/4

this fraction can be reduced to -3/2, which is the slope of the graph.

Now, use point slope form (y-y1=m(x-x1)) to find the equation of the graph. Plug any coordinate on the graph in for x1 and y1 here. It should be correct as long as it is a point on the graph, but I am using the point (-8, 18) here.

=>y-18=-3/2(x-(-8))

the double negative in the parentheses becomes a positive=> y-18=-3/2(x+8)

distribute the -3/2 to every term in the parentheses=> y-18=-3/2x-12

add 18 to both sides, cancelling out the -18 on the left side of the equation=>y=-3/2x+6 (-12+18=6 to get 6 for b).

Therefore, the equation is y=-3/2x+6

6 0
3 years ago
Need Help 2 & 3 with inequalities!!!
Mrac [35]

Answer:

2. D

3. B

Step-by-step explanation:

5 0
3 years ago
Help please!! :)))) Thanks!
baherus [9]
The answer is C. 16!!
5 0
3 years ago
I need help writing the first 5 terms of the sequence!
Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
4 years ago
Simplify 14 + 13 − (12 + 11). A) 0 B) 1 C) 4 D) 10
never [62]
C. 4
14 + 13 - (23)
27 - 23
4
4 0
3 years ago
Read 2 more answers
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