57.1 seconds = 57.1 seconds *

= 0.01057 hour
1 mile / 57.1 seconds = 1 mile / 0.01057 hour = 94.57 miles/hour
Answer:
it would be able to make 20 different sets. not at the same time though. you would only be able to make 2 at one time
Answer:
13r
Step-by-step explanation:
8+9=17-11=6+7=13
Answer:
AB is 16 units.
Step-by-step explanation:
Given:
AE = EC
BF = FC
EF = 8 and DF = 10
To Find:
AB = ?
Solution:
Mid Point Theorem:
The Midpoint Theorem states that "the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side".
AE = EC .....Given
Therefore E is the Mid Point of AC.
BF = FC .....Given
Therefore F is the Mid Point of BC.
Therefore,
EF || AB ........................Mid Point Theorem.
..............Mid Point Theorem.
Substituting the values we get
Therefore AB is 16 units.
Step-by-step explanation:
Answer:
If
then
and 
a | b | a + b (answer)
0 | 0 | 0
0 | 1 | 1
0 | 2 | 2
1 | 0 | 1
2 | 0 | 2
1 | 1 | 2
2 | 1 | 3
Step-by-step explanation:
Considering the following conditions for the real numbers:

Following the rules of these in-equations, it is possible to deduce:

Then, if the proposed statement is:

The conditions above shall comply the requirements established, but first, analyzing the statement:
If
and
then
,
and
.
If
and b a non negative real number, then
, but because to
, then
. Due to the commutative property of sums, the same behavior will be presented if
and a a non negative real number.
According to that, if
, then
and
.