Which polynomial equation of least degree has -2, -2, 3, and 3 as four of its roots? (x + 2)(x - 3) = 0 (x - 2)-2(x + 3)3 = 0 (x -2 + 2)(x2- 3) = 0 (x + 2)2(x - 3)2 = 0
1 answer:
Answer:
(x + 2)²(x - 3)² = 0
Step-by-step explanation:
Since we have a degree of 2 and double of the same roots, we know that each root would have a multiplicity of 2. Therefore, our answer is(x + 2)²(x - 3)² = 0
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