P of 1st white marble = 4/ 12
and P of 2nd white in a row = 3 /11
total = ( 4/12) * ( 3/11)
= 1/11
hope it helped
I believe its 45.
Its hard to explain but what I can say is if you subtract the percentage with the total of the skins you would subtract what you had from there and then you would have 45.
500×((1+0.06÷12)^(12×25)−1)÷(0.06÷12)
=346,496.98
Answer:
1c

1d

Step-by-step explanation:
From the question we are told that
The probability of telesales representative making a sale on a customer call is 
The mean is 
Generally the distribution of sales call made by a telesales representative follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the mean is mathematically represented as

=> 
=> 
Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

=> 
=> ![P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20%5B%20%5E%7Bn%7DC_0%20%2A%20%20%280.15%20%29%5E0%20%2A%20%20%281-%200.15%29%5E%7Bn-0%7D%5D%20%3E%200.95)
=> ![1 - [1 * 1* (0.85)^{n}] > 0.95](https://tex.z-dn.net/?f=%201%20-%20%5B1%20%20%2A%20%201%2A%20%20%280.85%29%5E%7Bn%7D%5D%20%3E%200.95)
=> ![[(0.85)^{n}] > 0.05](https://tex.z-dn.net/?f=%20%20%5B%280.85%29%5E%7Bn%7D%5D%20%3E%200.05)
taking natural log of both sides

=> 
Answer:
A) By using the Pythagorean Theorem, we will see that
. If we simplify it, we will find that the hypotenuse of Δ
B) approximately 
Step-by-step explanation:
A) In all honesty, you don't really need to look at ΔACD at all for this one. Just use the Pythagorean Theorem (like previously stated) and solve!
***Pythagorean Theorem is 
B) Here, you can also use the Pythagorean Theorem! However this time, the equation will be,
.
≈ 
Hope you do well on the rest of your math problems :D