It is d bexause every 6 is moved to the left for every one and it isnt abexause if you add 6 it would instwad go 6 12 18 24 and so on and its no c because if you move it to the right the # would decrease and obviously not b because if you subtract 0 every time it would stay as the same number

3 0

3 years ago

Read 2 more answers

Hello there are two questions in the link's if both were solved that would be awesome.

Stels [109]

Answer:

$\frac{x^{\frac{5}{6}} }{x^{\frac{1}{6}} } = x^{(\frac{5}{6} -\frac{1}{6}) }= x^{\frac{4}{6} }\\\sqrt{x} . \sqrt[4]{x} = x^{\frac{1}{2} } . x^{\frac{1}{4} } = x^{(\frac{1}{2} +\frac{1}{4}) } = x^{\frac{3}{4}$

7 0

3 years ago

Write an equivalent expression by distributing the "_" sign outside the parentheses: -k - (-6.2m+1)

nevsk [136]

Answer:

-k + (6.2m - 1)

Step-by-step explanation:

You distribute the negative to everything in the parentheses and change the sign to addition.

3 0

4 years ago

Joely's Tea Shop, a store that specializes in tea blends, has available 45 pounds of A grade tea and 70 pounds of B grade tea. T

prisoha [69]

Answer:

Hence, (75,40) is the maximum point and maximum profit is $192.5

Step-by-step explanation:

Let the breakfast be x

And let the lunch or afternoon be y

Inequalities will become

$\frac{1}{3}x+\frac{1}{2}y\leq 45$

$\frac{2}{3}x+\frac{1}{2}y\leq 70$

And objective function will be

Z=1.5x+2.0y

You can see the graph in the attachement

ABCD is the feasible region

Points of feasible region is (0,90) ,(0,0) ,(75,40) and(105,0)

We have to find Z by substituting the points of feasible region

At (0,90) we get

Z=1.5(0)+2(90)

Z=180

At (0,0)

Z=1.5(0)+2(0)

Z=0

At (75,40)

Z=1.5(75)+2(40)

Z=192.5

At (105,0)

Z=1.5(105)+2(0)

Z=157.5

The maximum number we are getting is 192.5 which is at (75,40)

Hence, (75,40) is the point of maximum

4 0

4 years ago